# Copyright (c) 2009 Google Inc. All rights reserved.

# Copyright (c) 2009 Apple Inc. All rights reserved.

#

# Redistribution and use in source and binary forms, with or without

# modification, are permitted provided that the following conditions are

# met:

#

#     * Redistributions of source code must retain the above copyright

# notice, this list of conditions and the following disclaimer.

#     * Redistributions in binary form must reproduce the above

# copyright notice, this list of conditions and the following disclaimer

# in the documentation and/or other materials provided with the

# distribution.

#     * Neither the name of Google Inc. nor the names of its

# contributors may be used to endorse or promote products derived from

# this software without specific prior written permission.

#

# THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS

# "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT

# LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR

# A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT

# OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,

# SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT

# LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,

# DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY

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import re

def plural(noun):

    # This is a dumb plural() implementation that is just enough for our uses.

    if re.search("h$", noun):

        return noun + "es"

    else:

        return noun + "s"

def pluralize(noun, count):

    if count != 1:

        noun = plural(noun)

    return "%d %s" % (count, noun)

def join_with_separators(list_of_strings, separator=', ', only_two_separator=" and ", last_separator=', and '):

    if not list_of_strings:

        return ""

    if len(list_of_strings) == 1:

        return list_of_strings[0]

    if len(list_of_strings) == 2:

        return only_two_separator.join(list_of_strings)

    return "%s%s%s" % (separator.join(list_of_strings[:-1]), last_separator, list_of_strings[-1])